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5=2x^2+95
We move all terms to the left:
5-(2x^2+95)=0
We get rid of parentheses
-2x^2-95+5=0
We add all the numbers together, and all the variables
-2x^2-90=0
a = -2; b = 0; c = -90;
Δ = b2-4ac
Δ = 02-4·(-2)·(-90)
Δ = -720
Delta is less than zero, so there is no solution for the equation
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